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Does Your Id Name Have Any Meaning?


BambinA

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well after join in TV member for a while ....before u start to be a member ..u need to apply and choose the name ... so what i want to know is...your ID imply something? have any meaning

me BambinA = a little girl ... well i choose it coz im always a baby silly girl

i try to guess (just copy who online right now)

thaibebop - he is in TH and be "bop"

Thomas_Merton - it'd be his real name

bangbuathongben- should be Ben who live in Bangbauthong

cobra - hmmmm sound dangerous

Lord Toad - frog's friend?

The_Moog - emmmm , but in thai Moog(k) = pearl

khall64au- must be a girl name K who come from Aus

mrbojangles - Mr Boj who love mathmetic stuff

bossman- bossy man>

Khun Jean- Mr .Jean

Ice Maiden - hmmmm tell me then

Totster - how about you danny?

britmaveric - come from UK?

tukyleith - hard to guess

Pattayaman- a man who lives in PTY

JustAnotherFarang - make sense

Rinrada- this is my real name

think_too_mut - too much for think?

sabai dee - im fine too

Nepal4me- from Nepal?

Boo- peek a BOO

loong - uncle

Firefoxx- sound like a web browser

CarlBkk - carl who live in Bkk

Boon Mee - that is Thai name

Bambi :o:D

ps...by the way there are more ID name who online now, i just dont know how to guess :D

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My TV nick is a version of my nickname which I have had since I was about 9yrs or 10yrs old...  :D
mrbojangles - Mr Boj who love mathmetic stuff

:D:D:D

totster :D

jing? danny...sound too diff from your name

BTW hope Mr. Boj who love math love 69 number :D:o

Lol.

My nickname basically says it all. I'm cold and biatchy also explains my fair skin. And "maiden" means an unmarried girl or woman :D . But I'm not always an Ice Maiden :D

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Nick name since youngster was maveric. I'm british. EasyPeasy!!! :D

i confest that i always imagine u are ..Mel Gibson from 1994 "Maverick"

My nickname basically says it all. I'm cold and biatchy also explains my fair skin. And "maiden" means an unmarried girl or woman  :D . But I'm not always an Ice Maiden  :D

talok mak mak

Gold star Bambi!  :D  I'm "a girl name K who come from Aus"  :D

i knew what K stand for ..but i wont tell anyone lol

LAMOK  :D

totster  :o

mai lomok mak .. just a lil :D

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My TV nick is a version of my nickname which I have had since I was about 9yrs or 10yrs old...  :D
mrbojangles - Mr Boj who love mathmetic stuff

:D:D

totster

jing? danny...sound too diff from your name

BTW hope Mr. Boj who love math love 69 number :D:D

:D:D

Hey Bambi, yeah 69 is about the only number i love. :o I would be intrigued to know how you came about the theory that i love mathematic stuff. This should make great reading :D:D

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Add more

(tell me if i guess wrong)

khunlungphudhu - its TH name ..ancient hi-so guy and pooh dee

sadako- sound like a ghost from "the ring" movie

FreedomDude- emmmm make sense

traveller57 - a back packer who born in1957?

bkkbrad - i know him , a brit who worked in BKK

S1MON - Simon

sexonlegs- cheeky

Sangsom - TH whiskey

wooooooooh ...

bambi :o

Edited by BambinA
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mrbojangles - Mr Boj who love mathmetic stuff

And for todays lesson boys and girls, we are going to build a rocket. Homework to be handed in to me tomorrow evening.

Let's use an Estes Alpha III, to keep it basic:

Weight: 1.2 ounces empty. I will add 0.7 ounces for the engine.

Diameter: 0.976 inches

Motor: C6-7 (we'll use a big one for this rocket)

Now let's follow the equations above and see what we get:

Compute the Useful Terms

Mass of the rocket M = (weight in ounces)/16/2.2 = (1.2+0.7) / 16 / 2.2 = 0.05398 kg

Area of the rocket: A = pi*r^2 = 3.14*(0.5*0.976/12*0.3048)^2 = 0.000483 m^2

Compute wind resistance factor: k = 0.5*rho*Cd*A = 0.5*1.2*0.75*0.000483 = 0.000217

A C6 motor has a nominal impulse of 10 N-s and thrust of 6 N. The "rating" cited above applies to the impulse, giving us an actual impulse for an Estes C6 of 10*90% = 9 N-s.

Compute the burn time t = I / T = 9 / 6 = 1.5 sec.

The gravitational force = M*9.8 = 0.05398*9.8 = 0.529 newton

Compute My Terms

q = sqrt([T - M*g] / k) = sqrt([6 - 0.05398*9.8] / 0.000217) = 158.8

x = 2*k*q / M = 2*0.000217*158.8 / 0.05398 = 1.277

Now the good stuff:

v = q*[1-exp(-x*t)] / [1+exp(-x*t)]

= 158.8*[1-exp(-1.277*1.5)] / [1+exp(-1.277*1.5)] = 118.0 m/s

if this number doesn't mean anything to you, multiply by 2.237 to get velocity at burn-out in mph: 118.0*2.237 = 264.0 mph! And you won't get a ticket!

yb = [-M / (2*k)]*ln([T - M*g - k*v^2] / [T - M*g])

= [-0.05398 / (2*0.000217)]*ln([6 - 0.05398*9.8 - 0.000217*118.0^2] / [6 - 0.05398*9.8]) = 99.95 m

remember this is the height reached during boost. Multiply by 3.3 to get it in feet: 99.95*3.3 = 329.8 feet.

yc = [+M / (2*k)]*ln([M*g + k*v^2] / [M*g])

= [+0.05398 / (2*0.000217)]*ln([0.05398*9.8 + 0.000217*118.0^2] / [0.05398*9.8])

= 236.8 m = 781.4 feet.

Notice: the rocket goes more than twice as far after the burn as during the burn!

AND THE TOTAL ALTITUDE IS... yb + yc = 329.8 + 781.4 = 1,111 feet :o

:D:D

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mrbojangles - Mr Boj who love mathmetic stuff

And for todays lesson boys and girls, we are going to build a rocket. Homework to be handed in to me tomorrow evening.

Let's use an Estes Alpha III, to keep it basic:

Weight: 1.2 ounces empty. I will add 0.7 ounces for the engine.

Diameter: 0.976 inches

Motor: C6-7 (we'll use a big one for this rocket)

Now let's follow the equations above and see what we get:

Compute the Useful Terms

Mass of the rocket M = (weight in ounces)/16/2.2 = (1.2+0.7) / 16 / 2.2 = 0.05398 kg

Area of the rocket: A = pi*r^2 = 3.14*(0.5*0.976/12*0.3048)^2 = 0.000483 m^2

Compute wind resistance factor: k = 0.5*rho*Cd*A = 0.5*1.2*0.75*0.000483 = 0.000217

A C6 motor has a nominal impulse of 10 N-s and thrust of 6 N. The "rating" cited above applies to the impulse, giving us an actual impulse for an Estes C6 of 10*90% = 9 N-s.

Compute the burn time t = I / T = 9 / 6 = 1.5 sec.

The gravitational force = M*9.8 = 0.05398*9.8 = 0.529 newton

Compute My Terms

q = sqrt([T - M*g] / k) = sqrt([6 - 0.05398*9.8] / 0.000217) = 158.8

x = 2*k*q / M = 2*0.000217*158.8 / 0.05398 = 1.277

Now the good stuff:

v = q*[1-exp(-x*t)] / [1+exp(-x*t)]

= 158.8*[1-exp(-1.277*1.5)] / [1+exp(-1.277*1.5)] = 118.0 m/s

if this number doesn't mean anything to you, multiply by 2.237 to get velocity at burn-out in mph: 118.0*2.237 = 264.0 mph! And you won't get a ticket!

yb = [-M / (2*k)]*ln([T - M*g - k*v^2] / [T - M*g])

= [-0.05398 / (2*0.000217)]*ln([6 - 0.05398*9.8 - 0.000217*118.0^2] / [6 - 0.05398*9.8]) = 99.95 m

remember this is the height reached during boost. Multiply by 3.3 to get it in feet: 99.95*3.3 = 329.8 feet.

yc = [+M / (2*k)]*ln([M*g + k*v^2] / [M*g])

= [+0.05398 / (2*0.000217)]*ln([0.05398*9.8 + 0.000217*118.0^2] / [0.05398*9.8])

= 236.8 m = 781.4 feet.

Notice: the rocket goes more than twice as far after the burn as during the burn!

AND THE TOTAL ALTITUDE IS... yb + yc = 329.8 + 781.4 = 1,111 feet :o

:D :wacko:

i reckon the final answer = 69

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I'm a Libertarian.  I believe that governments should leave people alone as long as they're not hurting or stealing from anyone else.

Libertarian Party

CATO Institute

So , read any good books lately?

OOps sorry. Libertarian. not librarian! :D

Anyway

23 x 3 = well I could tell you the answer in Russian, but its rather a mouthfull :D

23 x 3 = sometimes only 34 and half (think about it) :o

23 x 3 = sometimes "I no like*

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