new house with pool and a need to balance the water. Trial & error is an option of course.

But some SIMPLE advice is now asked for. It has 2 straight sides and the remainder is curved. 2 sets of wide tiled steps. A shallow and a deep end. What's the simple way to 'guesstimate' (best guess) the water capacity for water balancing? Dont have or know how to use a slide rule (remember those??)

Thanks in advance

Hope this does the trick:

http://www.pentairpool.com/save-energy/calculators/pool-volume-calc/poolcalc.htm

http://www.backyardcitypools.com/Pool-Volume-Calculate.htm

Regards MS>

Moved to swimming pool forum

You could plot the area on a piece of graph paper, but I would try to imagine what size it would be if it was rectangular. Then you have the area in square metres (length x width). If the slope from shallow to deep end is gradual with no shelf then add the depth at the shallow end to the depth at the deep end and divide by two to give the average depth (it's back to that graph paper or imagination if there is a shelf). Multiply the area by the average depth and take off a little bit (say 5%) for the steps and there you have it - volume in cubic metres.

And here is a pool chemistry calculator website

http://www.poolcalculator.com/