Beer Mathematics

[custard]

This takes less than a minute.......

DON'T CHEAT BY SCROLLING DOWN FIRST!

Be sure you don't read the bottom until you've worked it out!

1. First of all, pick the number of times a week that you would like to have a pint or two.

2. Multiply this number by 2 (just to get an honest figure)

3 Add 5 (for Sunday)

4. Multiply it by 50. I'll wait while you get the calculator................

5. If you have already had your birthday this year add 1755. If you haven't, add 1754

6. Now subtract the four-digit year that you were born.

You should have a three-digit number

The first digit of this was your original number (i.e., how many times you want to have a pint this week).

The next two numbers are .......

…………..YOUR AGE!

THIS IS THE ONLY YEAR IT WILL EVER WORK, SO SPREAD IT AROUND WHILE IT LASTS.

[custard]

1. 2

2. 2 = 4

3. 5 = 9

4. 50 = 450

5. 1754 = 2204

6. 1983 = 0221

0221

[mrbojangles]

1. 2

2. 2 = 4

3. 5 = 9

4. 50 = 450

5. 1754 = 2204

6. 1983 = 0221

0221

Blimey Custard, at 21 you only want to go out twice a week

Mine is

1. 7

2. 2 = 14

3. 5 = 19

4. 50 = 950

5. 1754 = 2704

6. 1963 = 0741

Might have to change when the wifes visa comes through though

do it while i can

Mr BoJ

[custard]

Blimey Custard, at 21 you only want to go out twice a week 

<{POST_SNAPBACK}>

Basically I'm a responsible person or perhaps I'm just too lightweight ?

[RDN]

1. 2

2. 2 = 4

3. 5 = 9

4. 50 = 450

5. 1754 = 2204

6. 1983 = 0221

0221

<{POST_SNAPBACK}>

1. "x"

2. 2x

3. 2x + 5

4. (2x + 5) X 50 = (100x + 250)

5. (100x + 250) + (1754 or 1755) = 100x + (2004 or 2005)

So the first digit (in the "hundreds" position) will always be "x" - the number of times you want to drink

and the last two digits will obviously be your age (this year - birth year) - unless you're 100 years old or more

Next!

[dereklev]

1. 2

2. 2 = 4

3. 5 = 9

4. 50 = 450

5. 1754 = 2204

6. 1983 = 0221

0221

1. "x"

2. 2x

3. 2x + 5

4. (2x + 5) X 50 = (100x + 250)

5. (100x + 250) + (1754 or 1755) = 100x + (2004 or 2005)

So the first digit (in the "hundreds" position) will always be "x" - the number of times you want to drink

and the last two digits will obviously be your age (this year - birth year) - unless you're 100 years old or more

Next!

Not bad for 4.45 in the morning RDN!!

Was that before or after some sleep.....

Very nice meeting you on Friday and look forward to seeing you again soon.

[RDN]

Not bad for 4.45 in the morning RDN!!

Was that before or after some sleep.....

Very nice meeting you on Friday and look forward to seeing you again soon.

<{POST_SNAPBACK}>

No sleep yet, but just got in from - guess what? - playing pool at a bar in Rawai.

It was good to chat to you too - I'm sure I'll see you at another meet-up soon. Cheers!

[custard]

So the first digit (in the "hundreds" position) will always be "x" - the number of times you want to drink

and the last two digits will obviously be your age (this year - birth year) - unless you're 100 years old or more

Next!

<{POST_SNAPBACK}>

Cheers for that. I'm a Maths idiot (nearly failed it at GCSE ! )

[mpdkorat]

So the first digit (in the "hundreds" position) will always be "x" - the number of times you want to drink

and the last two digits will obviously be your age (this year - birth year) - unless you're 100 years old or more

Next!

<{POST_SNAPBACK}>

Cheers for that. I'm a Maths idiot (nearly failed it at GCSE ! )

<{POST_SNAPBACK}>

Hey custard can you help me with this GSCE thing. Sounds like a venereal disease I keep failing those tests. BTW I'm an idiot too.

[itsme]

Blimey Custard, at 21 you only want to go out twice a week 

<{POST_SNAPBACK}>

Basically I'm a responsible person or perhaps I'm just too lightweight ?

<{POST_SNAPBACK}>

Same as mine 0741

Who else got it 7 on the first number?