Alcohol Maths

[choppychugger]

YOUR AGE BY ALCOHOL MATHS

This is pretty neat.

DON'T CHEAT BY SCROLLING DOWN FIRST!

It takes less than a minute.

Work this out as you read.

Be sure you don't read the bottom until you've worked it out!

This is not one of those waste of time things, it's fun.

1. First of all, pick the number of times a week that you would like to have alcohol (more than once but less than 10)

2. Multiply this number by 2 (just to be bold)

3. Add 5

4. Multiply it by 50 -- I'll wait while you get the calculator

5. If you have already had your birthday this year add 1759 ..

If you haven't, add 1758.

6. Now subtract the four digit year that you were born.

You should have a three digit number

The first digit of this was your original number

(i.e., how many times you want to have alcohol each week).

The next two numbers are

YOUR AGE! (Oh YES, it is!!!!!)

THIS IS THE ONLY YEAR (2009) IT WILL EVER WORK

[mauGR1]

Stunning..

[mmmarcus]

What tha <deleted>!!?? hahaha

Edited August 7, 2009 by mmmarcus

[Samuian]

Stunning..

Why, which 3 digit number did you and up?

well math's... after all...

[mauGR1]

Stunning..

Why, which 3 digit number did you and up?

well math's... after all...

Well,the real stun was that my math was right

[wileycoyote]

Excellent

Mike

[mmushr00m]

wow thats cool.

lol actually the 1st time I did it I got the math wrong (a reason why I am not an engineer).

[philo]

There is nothing stunning or magical about this - it is just an algebraic triviality:

Call the number of drinking days X.

Multply by 2 - get 2X. Add 5 and get (2X+5). Multiply by 50: (2X+5)*50 = 100X + 250.

Not yet birthday this year: Add 1758 - Get : 100X + 250 + 1758. Subract your birth year: 19.. = 1900 + (108-A), where A is your age.

(Example: You are 29 (not yet 30 this year) - 19.. is 1979, and 1900 + (108-29) = 1979.)

So : 100X + 250 + 1758 - (1900 + (108 - A)) is the number.

(Please note that 250 + 1758 = 2008, and when you subtract 1900 the number is 108.)

The answer: The number of drinking days plus your age can be expressed as 100X+A, i.e. 2 days and age 29 will give 229.

The simple identity is:

(2X + 5) * 50 + 1758 - (1900 +(108-A)) = 100X + A

100X + 250 + 1758 - 1900 -108 + A = 100X +A

100X + 108 - 108 + A = 100X +A

q.e.d.

[choppychugger]

^ ermmmm thanks for breaking that down. I was just about to work out the Algabraic equations for everyone, but you beat me to it.

Choppy

[philo]

Hi choppy.

Good to see another fellow mathematician.

My argument - though correct - is a bit lacking (due to the fact that I was not sober and had to babysit (they were sleeping, but were about to wake up before I could proof read the post)).

Please refine the argument by showing that having had one's birthday already requires addittion of the number 1759 (one 'year' older).

philo

[choppychugger]

You got me there Philo. I posted this for a bit of fun not thinking anyone would actually break it down.

Will have another look at it.

Choppy

[lovelaos]

Some people are too clever (and boring) for their own good

[philo]

Some people are too clever (and boring) for their own good

Agree.

philo

[philo]

Well, as I am bored to death (drinking Heineken) waiting for my wife and children to wake up so we can go to get a pizza with pepperoni and blue cheese - here it is:

Call the number of drinking days X and your age A. You are supposed to have had your birthday already this year.

(2X + 5) * 50 + 1759 - (1900 + (109-A)) = 100X + A

100X + 250 + 1759 - 1900 - 109 + A = 100X + A

100X + 109 - 109 + A = 100X + A

100X + A = 100X + A

0 = 0 (I like this one ...)

OK - you are born in March 1957, so you are 52. You drink 7 days a week (like me).

(2 * 7 + 5) * 50 + 1759 - (1900 + (109 - 52) = 100 * 7 + 52 = 752 (sic)

philo

PS I will leave it to a Post Doctorate WBU (Water Buffallo University) Research Fellow to show that it can be modified to apply for 2010 ad infinitum.

But now I go for the pizza ...

philo

[PeaceBlondie]

Since I haven't wanted a drink in forty years, I stopped at step 1.

[suegha]

This is just a simple 'sum'. It's not only applicable this year, with a small adjustment you can do it every year. It's actually an old one. I heard it about five years ago counting the number of times you'd like to go out for a meal - it could be any thing...

[Harcourt]

Since I haven't wanted a drink in forty years, I stopped at step 1.

Substitute "drinking" with "having sex" or "going fishing".

[Harcourt]

There's another one, with variations:

Get your patsy to think of a number, more than 1, less than 10...multiply by 9, add the 2 digits (18: 1 + 8, 27: 2+7, 36: 3+6 etc, 45, 54, 63, etc). At this point you know what the number your patsy has as a result, it will always be 9, so you can carry on from here with all sorts of mathematic acrobatics to finally announce a result that "you couldn't possibly have guessed unless you read the patsy's mind" or unless you are a mathemagician.

I always manipulate them to get a result of 1, but not tell me, and then carry on to get 5, and not tell me.

Once they have 1 and 5 in their mind, thinking I don't know, I get them to translate the numbers to letters: A=1, B=2, C=3 etc. So they now have A and E in their mind. Now think of a country (99% will think Australia) and think of an animal (99% will think elephant)....use your own punchline to "read their mind" such as, "I'm getting Australia, but I'm confused because elephants don't come from Australia..."

[kurnell]

Are there more than 7 days in a week?

[philo]

Are there more than 7 days in a week?

Sorry, I don't know. I will have to check it out on the internet.

The OP was talking about how many TIMES a week you want to drink (2-9).

For me this number is non-existant: I drink all day all days all weeks all months all years ... So in my world: 7 times a week is not appliable. 7 days a week is - and please note that 7 days a week is not the same as 7 days a month or 7 seven days a year.

But if I can sober up a little I will try to find the answer to your question.

philo

[suegha]

In the decimal world there are 10 days and the tenth day is the sabbath.

[Harcourt]

In the decimal world there are 10 days and the tenth day is the sabbath.

Nice, but irrelevant.....in the digital world there are 8 days, and the eighth day is the byte.

[Patsycat]

I didn't know i was so old.