A(0) / 2 + (k=1..) [ A(k) cos (k(PI)x / m) + B(k) (sin k(PI)x / m) ]

a(k) = 1/m f(x) cos (k(PI)x / m) dx

b(k) = 1/m f(x) sin (k(PI)x / m) dx

f(x) = ( a(y) cos yx + b(y) sin yx ) dy

Dn(x) = Dirichlet kernel = 1/2 + cos x + cos 2x + .. + cos nx = [ sin(n + 1/2)x ] / [ 2sin(x/2) ]

a(y) = 1/PI f(t) cos ty dt

b(y) = 1/PI f(t) sin ty dt

f(x) = 1/PI dy f(t) cos (y(x-t)) dt

1/PI f^2(x) dx = a(0)^2 / 2 + (k=1..) (a(k)^2 + b(k)^2)

g(x) = (2/PI)f(t) cos xt dt

[ \frac{a(0)}{2} + \sum_{k=1}^\infty (a(k) \cos kx + b(k) \sin kx) \]

f(x) = e^(-xt) g(t) dt

f(x) = e^(-xt) g(t) d(t)

f2(x) = L{L{g(t)}} = g(t)/(x+t) dt

The above proves, mathematically, beyond a shadow of a doubt that I will have the Last Word. Figure these simple formulae out for yourselves. You'll see exactly what I'm talking about.

A(0) / 2 + (k=1..) [ A(k) cos (k(PI)x / m) + B(k) (sin k(PI)x / m) ]

a(k) = 1/m f(x) cos (k(PI)x / m) dx

b(k) = 1/m f(x) sin (k(PI)x / m) dx

f(x) = ( a(y) cos yx + b(y) sin yx ) dy

Dn(x) = Dirichlet kernel = 1/2 + cos x + cos 2x + .. + cos nx = [ sin(n + 1/2)x ] / [ 2sin(x/2) ]

a(y) = 1/PI f(t) cos ty dt

b(y) = 1/PI f(t) sin ty dt

f(x) = 1/PI dy f(t) cos (y(x-t)) dt

1/PI f^2(x) dx = a(0)^2 / 2 + (k=1..) (a(k)^2 + b(k)^2)

g(x) = (2/PI)f(t) cos xt dt

[ \frac{a(0)}{2} + \sum_{k=1}^\infty (a(k) \cos kx + b(k) \sin kx) \]

f(x) = e^(-xt) g(t) dt

f(x) = e^(-xt) g(t) d(t)

f2(x) = L{L{g(t)}} = g(t)/(x+t) dt

The above proves, mathematically, beyond a shadow of a doubt that I will have the Last Word. Figure these simple formulae out for yourselves. You'll see exactly what I'm talking about.

E = mc2 .............. love ya bro!

Okay Tip.... I´m an ex maths teacher.

I´m afraid I must inform you that you have made one TOO many mathematical errors in the past academic year.

Not only will you have to redo the year, but you will be put on probabtionary detention until you´re grades improve.

I have further more been led to understand that you waste a lot of valuable study/drinking time on anonymous forums on the internet.

Hence, you are no longer permitted to use the internet other than to check your emails, and correspond accordingly.

Yours truly,

TLW.

edit: Klown Font.

well say Kayo...Tipp you are out of here...

Glauka, no kissing hte teacher´s arse... But you can kiss me here.... and here... oh! and there!

Glauka, no kissing hte teacher´s arse... But you can kiss me here.... and here... oh! and there!

Not fair ... Tippy bro' - fight back! This team -just-does-NOT-quite-cut-it!!!!!

A(0) / 2 + (k=1..) [ A(k) cos (k(PI)x / m) + B(k) (sin k(PI)x / m) ]

a(k) = 1/m f(x) cos (k(PI)x / m) dx

b(k) = 1/m f(x) sin (k(PI)x / m) dx

f(x) = ( a(y) cos yx + b(y) sin yx ) dy

Dn(x) = Dirichlet kernel = 1/2 + cos x + cos 2x + .. + cos nx = [ sin(n + 1/2)x ] / [ 2sin(x/2) ]

a(y) = 1/PI f(t) cos ty dt

b(y) = 1/PI f(t) sin ty dt

f(x) = 1/PI dy f(t) cos (y(x-t)) dt

1/PI f^2(x) dx = a(0)^2 / 2 + (k=1..) (a(k)^2 + b(k)^2)

g(x) = (2/PI)f(t) cos xt dt

[ \frac{a(0)}{2} + \sum_{k=1}^\infty (a(k) \cos kx + b(k) \sin kx) \]

f(x) = e^(-xt) g(t) dt

f(x) = e^(-xt) g(t) d(t)

f2(x) = L{L{g(t)}} = g(t)/(x+t) dt

I really must get those Thai fonts installed on this PC....

totster

A(0) / 2 + (k=1..) [ A(k) cos (k(PI)x / m) + B(k) (sin k(PI)x / m) ]

a(k) = 1/m f(x) cos (k(PI)x / m) dx

b(k) = 1/m f(x) sin (k(PI)x / m) dx

f(x) = ( a(y) cos yx + b(y) sin yx ) dy

Dn(x) = Dirichlet kernel = 1/2 + cos x + cos 2x + .. + cos nx = [ sin(n + 1/2)x ] / [ 2sin(x/2) ]

a(y) = 1/PI f(t) cos ty dt

b(y) = 1/PI f(t) sin ty dt

f(x) = 1/PI dy f(t) cos (y(x-t)) dt

1/PI f^2(x) dx = a(0)^2 / 2 + (k=1..) (a(k)^2 + b(k)^2)g(x) = (2/PI)f(t) cos xt dt

[ \frac{a(0)}{2} + \sum_{k=1}^\infty (a(k) \cos kx + b(k) \sin kx) \]

f(x) = e^(-xt) g(t) dt

f(x) = e^(-xt) g(t) d(t)

f2(x) = L{L{g(t)}} = g(t)/(x+t) dt

The above proves, mathematically, beyond a shadow of a doubt that I will have the Last Word. Figure these simple formulae out for yourselves. You'll see exactly what I'm talking about.

See above in bold

Sorry, it's not correct!

It should be: = a(0)^2 / 2 + (k=1..)..f_3ck ./. y_2o (a(k)^2 + b(k)^2)

The rest is correct.

LaoPo

A(0) / 2 + (k=1..) [ A(k) cos (k(PI)x / m) + B(k) (sin k(PI)x / m) ]

a(k) = 1/m f(x) cos (k(PI)x / m) dx

b(k) = 1/m f(x) sin (k(PI)x / m) dx

f(x) = ( a(y) cos yx + b(y) sin yx ) dy

Dn(x) = Dirichlet kernel = 1/2 + cos x + cos 2x + .. + cos nx = [ sin(n + 1/2)x ] / [ 2sin(x/2) ]

a(y) = 1/PI f(t) cos ty dt

b(y) = 1/PI f(t) sin ty dt

f(x) = 1/PI dy f(t) cos (y(x-t)) dt

1/PI f^2(x) dx = a(0)^2 / 2 + (k=1..) (a(k)^2 + b(k)^2)g(x) = (2/PI)f(t) cos xt dt

[ \frac{a(0)}{2} + \sum_{k=1}^\infty (a(k) \cos kx + b(k) \sin kx) \]

f(x) = e^(-xt) g(t) dt

f(x) = e^(-xt) g(t) d(t)

f2(x) = L{L{g(t)}} = g(t)/(x+t) dt

The above proves, mathematically, beyond a shadow of a doubt that I will have the Last Word. Figure these simple formulae out for yourselves. You'll see exactly what I'm talking about.

See above in bold

Sorry, it's not correct!

It should be: = a(0)^2 / 2 + (k=1..)..f_3ck ./. y_2o (a(k)^2 + b(k)^2)

The rest is correct.

LaoPo

Who is the MAN? LaoPo........... Do you mind if I send this formulae to my niece?

A(0) / 2 + (k=1..) [ A(k) cos (k(PI)x / m) + B(k) (sin k(PI)x / m) ]

a(k) = 1/m f(x) cos (k(PI)x / m) dx

b(k) = 1/m f(x) sin (k(PI)x / m) dx

f(x) = ( a(y) cos yx + b(y) sin yx ) dy

Dn(x) = Dirichlet kernel = 1/2 + cos x + cos 2x + .. + cos nx = [ sin(n + 1/2)x ] / [ 2sin(x/2) ]

a(y) = 1/PI f(t) cos ty dt

b(y) = 1/PI f(t) sin ty dt

f(x) = 1/PI dy f(t) cos (y(x-t)) dt

1/PI f^2(x) dx = a(0)^2 / 2 + (k=1..) (a(k)^2 + b(k)^2)g(x) = (2/PI)f(t) cos xt dt

[ \frac{a(0)}{2} + \sum_{k=1}^\infty (a(k) \cos kx + b(k) \sin kx) \]

f(x) = e^(-xt) g(t) dt

f(x) = e^(-xt) g(t) d(t)

f2(x) = L{L{g(t)}} = g(t)/(x+t) dt

The above proves, mathematically, beyond a shadow of a doubt that I will have the Last Word. Figure these simple formulae out for yourselves. You'll see exactly what I'm talking about.

See above in bold

Sorry, it's not correct!

It should be: = a(0)^2 / 2 + (k=1..)..f_3ck ./. y_2o (a(k)^2 + b(k)^2)

The rest is correct.

LaoPo

Who is the MAN? LaoPo........... Do you mind if I send this formulae to my niece?

No problem.....your niece might know the formula already

LaoPo

You realize that you are fooling with the forces of nature when you start creating such formulae ?

You could very well unleash a wave of ennui that could result in only me having the last word (as I am immune to ennui) !

Good work Tippaporn !

I cant believe Kerry has had the last word for like 10 hours. Ohh well not now ehhh

Gutted.......!

He'll get over it....!

redrus

A(0) / 2 + (k=1..) [ A(k) cos (k(PI)x / m) + B(k) (sin k(PI)x / m) ]

a(k) = 1/m f(x) cos (k(PI)x / m) dx

b(k) = 1/m f(x) sin (k(PI)x / m) dx

f(x) = ( a(y) cos yx + b(y) sin yx ) dy

Dn(x) = Dirichlet kernel = 1/2 + cos x + cos 2x + .. + cos nx = [ sin(n + 1/2)x ] / [ 2sin(x/2) ]

a(y) = 1/PI f(t) cos ty dt

b(y) = 1/PI f(t) sin ty dt

f(x) = 1/PI dy f(t) cos (y(x-t)) dt

1/PI f^2(x) dx = a(0)^2 / 2 + (k=1..) (a(k)^2 + b(k)^2)

g(x) = (2/PI)f(t) cos xt dt

[ \frac{a(0)}{2} + \sum_{k=1}^\infty (a(k) \cos kx + b(k) \sin kx) \]

f(x) = e^(-xt) g(t) dt

f(x) = e^(-xt) g(t) d(t)

f2(x) = L{L{g(t)}} = g(t)/(x+t) dt

The above proves, mathematically, beyond a shadow of a doubt that I will have the Last Word. Figure these simple formulae out for yourselves. You'll see exactly what I'm talking about.

OK, I'll bite - does the formula mean anything or is it the product of a sick mind? (If the former, could you explain in really really easy terms, as I managed Maths 'O' Level in 1977 and have progressed no further in the Queen of Sciences since that point).

I have coffee.

Just what would all you people be doing with your time if it wasn't for this thread ?

And to think I have the power...............

yeah but "Power is nothing without control"

you reckon you have control in this thread...?

you may have started it - but its gone way past sensible now

TLW

666

And to think I have the power...............

Who do you think you are? <deleted> he-man? Is that the power of greyskull? Numpty!!!!!!!

Spoke to Rus last night on the phone, you wanna hear what he said about you

And to think I have the power...............

Who do you think you are? <deleted> he-man? Is that the power of greyskull? Numpty!!!!!!!

Spoke to Rus last night on the phone, you wanna hear what he said about you

Put yer spoon away DB...............!!!!!

redrus

Put yer spoon away DB...............!!!!!

redrus

Its big and wooden as well

Put yer spoon away DB...............!!!!!

redrus

Its big and wooden as well

We'll take your word for it.

It wouldn't be fair to ask your wife.

Put yer spoon away DB...............!!!!!

redrus

Its big and wooden as well

We'll take your word for it.

It wouldn't be fair to ask your wife.

Naa no need to ask her mate, that is just big wood

And to think I have the power...............

Who do you think you are? <deleted> he-man? Is that the power of greyskull? Numpty!!!!!!!

Spoke to Rus last night on the phone, you wanna hear what he said about you

Put yer spoon away DB...............!!!!!

redrus

You wanna hear what he's said about you rus !!!

totster

yaaaaaawwwwwwnnnnnn

yaaaaaawwwwwwnnnnnn

Yeah, exactly.

Perhaps someone should point certain people to the chat forum that was set up for stuff like this ?

After all, the point here is to have the Last Word. Putting Glauka to sleep is no challenge

yaaaaaawwwwwwnnnnnn

Yeah, exactly.

Perhaps someone should point certain people to the chat forum that was set up for stuff like this ?

After all, the point here is to have the Last Word. Putting Glauka to sleep is no challenge

<deleted>

yaaaaaawwwwwwnnnnnn

Yeah, exactly.

Perhaps someone should point certain people to the chat forum that was set up for stuff like this ?

After all, the point here is to have the Last Word. Putting Glauka to sleep is no challenge

<deleted>

Is NOT !

yaaaaaawwwwwwnnnnnn

Yeah, exactly.

Perhaps someone should point certain people to the chat forum that was set up for stuff like this ?

After all, the point here is to have the Last Word. Putting Glauka to sleep is no challenge

<deleted>

Is NOT !

Is SO

Is NOT !

Is SO

I did that on purpose as a psychiatric test. I was sure you would respond in kind, and you did. The euphoria of having a new baby has reduced your level of intelligent response to the Grade 2-3 level. At this rate you'll be reduced to pure gibberish (a sound medical term !) in the near future (I would estimate 6 weeks, or just about the time you arrive in LOS !)

Word.